Question

8x^2+6x^3
x^3-5x^2-4x+20
x^2-9y^2-4x+4 
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Answer 1

\(8x^2+6x^3=2x^2\left(4+3x\right)\)

\(x^3-5x^2-4x+20=x^2\left(x-5\right)-4\left(x-5\right)=\left(x^2-4\right)\left(x-5\right)=\left(x-2\right)\left(x+2\right)\left(x-5\right)\)

\(x^2-9y^2-4x+4=\left(x^2-4x+4\right)-\left(3y\right)^2=\left(x-2\right)^2-\left(3y\right)^2=\left(x-2-3y\right)\left(x-2+3y\right)\)

Answer 2

a: \(8x^2+6x^3=2x^2\left(4+3x\right)\)

b: \(x^3-5x^2-4x+20\)

\(=x^2\left(x-5\right)-4\left(x-5\right)\)

\(=\left(x-5\right)\left(x-2\right)\left(x+2\right)\)

c: \(x^2-4x+4-9y^2\)

\(=\left(x-2\right)^2-9y^2\)

\(=\left(x-2-3y\right)\left(x-2+3y\right)\)