Question

7 chia hết cho (x- 4)

Answer 1

\(7⋮x-4\)

\(\Rightarrow x-4\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)

Xét bảng :

x-4	1	-1	7	-7
x	5	3	11	-3

Vậy....

Answer 2

Ta có: 7 \(⋮\) x-4

\(\Rightarrow x-4\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)

\(\Rightarrow x\in\left\{5;3;11;-3\right\}\)

Vậy: \(x\in\left\{5;3;11;-3\right\}\)