Question

(6x+4) chia hết cho (2x-1)
bạn nào giỏi toán làm giúp mình gấp với

Answer 1

\(\Rightarrow3\left(2x-1\right)+7⋮\left(2x-1\right)\\ \Rightarrow2x-1\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\\ \Rightarrow2x\in\left\{-6;0;2;8\right\}\\ \Rightarrow x\in\left\{-3;0;1;4\right\}\)

Answer 2

\(\Leftrightarrow2x-1\in\left\{1;-1;7;-7\right\}\)

hay \(x\in\left\{1;0;4;-3\right\}\)

Answer 3

⇒3(2x−1)+7⋮(2x−1)⇒2x−1∈Ư(7)={−7;−1;1;7}⇒2x∈{−6;0;2;8}⇒x∈{−3;0;1;4