\(\dfrac{4a-4b}{5a+5b}.x=\dfrac{a^2-b^2}{a^2+2ab+b^2}\)
\(\Leftrightarrow\dfrac{4\left(a-b\right)}{5\left(a+b\right)}.x=\dfrac{\left(a-b\right)\left(a+b\right)}{\left(a+b\right)^2}\)
\(\Leftrightarrow x=\dfrac{a-b}{a+b}.\dfrac{5\left(a+b\right)}{4\left(a-b\right)}\)
\(\Leftrightarrow x=\dfrac{5}{4}\)
Vậy \(x=\dfrac{5}{4}\)
Ta có: \(\dfrac{4\left(a-b\right)}{5\left(a+b\right)}x=\dfrac{\left(a-b\right)\left(a+b\right)}{\left(a+b\right)^2}\)
\(\Rightarrow\)\(\dfrac{4\left(a-b\right)}{5\left(a+b\right)}x=\dfrac{a-b}{a+b}\)\(\Rightarrow\dfrac{4}{5}x=\dfrac{a-b}{a+b}.\dfrac{a+b}{a-b}=1\)
\(\Rightarrow\)x = \(1:\dfrac{4}{5}=\dfrac{5}{4}\)
Chúc các bạn học tốt
=> \(\dfrac{4\left(a-b\right)}{5\left(a+b\right)}x=\dfrac{\left(a-b\right)\left(a+b\right)}{\left(a+b\right)^2}\)
=> \(\dfrac{4}{5}.\dfrac{a-b}{a+b}x=\dfrac{a-b}{a+b}\)
=> \(\dfrac{4}{5}x=1\)
=> \(x=\dfrac{5}{4}\)
