1:
a: \(=\dfrac{6^5}{3^5}=2^5=32\)
b: \(=\dfrac{5^4\cdot2^4}{5^5\cdot\left(-2\right)^5}=\dfrac{1}{5}\cdot\dfrac{-1}{2}=\dfrac{-1}{10}\)
Bài 2:
a: \(\Leftrightarrow\left(\dfrac{1}{3}\right)^m=\left(\dfrac{1}{3}\right)^4\)
hay m=4
b: \(\Leftrightarrow\left(\dfrac{3}{5}\right)^n=\left(\dfrac{3}{5}\right)^{10}\)
hay n=10