Question

(5x\(^3\)y\(^2\)+2x\(^2\)y\(^2\)-10x\(^2\)y\(^4\)):5x\(^2\)y\(^2\)

Answer 1

đề bài

Answer 2

(5x${}^{}$y${}^{}$+2x${}^{}$y${}^{}$-10x${}^{}$y${}^{}$):5x${}^{}$y${}^{}$

-2y²

Answer 3

(5x${}^{}$y${}^{}$+2x${}^{}$y${}^{}$-10x${}^{}$y${}^{}$):5x${}^{}$y${}^{}$

= x+ \(\dfrac{2}{5}\) -2y²

Answer 4

( 5x³y² + 2x²y² - 10x²y⁴) : 5x²y²

Ta có : 5x²y²( x + \(\dfrac{2}{5}\)- 2y²) : 5x²y²

Vậy , thương là :R = x + \(\dfrac{2}{5}\)- 2y²

Answer 5

\(\left(5x^3y^2+2x^2y^2-10x^2y^4\right):5x^2y^2\)

\(=5x^3y^2:5x^2y^2+2x^2y^2:5x^2y^2-10x^2y^4:5x^2y^2\)

\(=x+\dfrac{2}{5}-2y^2\)