\(\left(5x-2y\right)\left(x-3\right)=0\)
\(\Rightarrow5x-2y=0\)
\(\Rightarrow x-3=0\Rightarrow x=3\)
\(5.3-2y=0\)
\(15=2y\)
\(y=\dfrac{15}{2}\)
\(\left(5x-2y\right)\left(x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-2y=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}2y=5.3\\x=3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}y=\dfrac{15}{2}\\x=3\end{matrix}\right.\)
Vậy................
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