\(\sqrt{54}+4\sqrt{24}+3.\sqrt{216}\)
\(=\sqrt{3^2.6}+4.\sqrt{2^2.6}+3.\sqrt{6^2.6}\)
\(=3\sqrt{6}+8\sqrt{6}+18\sqrt{6}\)
\(=29\sqrt{6}\)
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Bài 2: Căn thức bậc hai và hằng đẳng thức căn bậc hai của bình phương
Các câu hỏi tương tự
câu 1 : thực hiện phép tính
a) sqrt{50}-sqrt{54}+frac{1}{2}sqrt{72}+frac{5}{6}sqrt{216}
b) frac{1}{2}sqrt{48}-sqrt{32}-sqrt{75}-frac{1}{5}sqrt{50}
c)frac{sqrt{2}-1}{2-sqrt{2}}
d)4sqrt{frac{3}{2}}-frac{5}{2}sqrt{24}+frac{1}{2}sqrt{32}
e)24sqrt{frac{2}{3}}+6sqrt{frac{3}{2}}-3sqrt{24}
f)2sqrt{12}+3sqrt{27}-sqrt{48}
g)left(2sqrt{5}+5sqrt{2}right).sqrt{5}-sqrt{250}
h)frac{3+sqrt{3}}{3-sqrt{3}}+frac{3-sqrt{3}}{3+sqrt{3}}
k)left(sqrt{28}-sqrt{12}+sqrt{7}right).sqrt{7}+2.sqrt{21}
l)frac{2.sqr...
Đọc tiếp
câu 1 : thực hiện phép tính
a) \(\sqrt{50}-\sqrt{54}+\frac{1}{2}\sqrt{72}+\frac{5}{6}\sqrt{216}\)
b) \(\frac{1}{2}\sqrt{48}-\sqrt{32}-\sqrt{75}-\frac{1}{5}\sqrt{50}\)
c)\(\frac{\sqrt{2}-1}{2-\sqrt{2}}\)
d)\(4\sqrt{\frac{3}{2}}-\frac{5}{2}\sqrt{24}+\frac{1}{2}\sqrt{32}\)
e)\(24\sqrt{\frac{2}{3}}+6\sqrt{\frac{3}{2}}-3\sqrt{24}\)
f)\(2\sqrt{12}+3\sqrt{27}-\sqrt{48}\)
g)\(\left(2\sqrt{5}+5\sqrt{2}\right).\sqrt{5}-\sqrt{250}\)
h)\(\frac{3+\sqrt{3}}{3-\sqrt{3}}+\frac{3-\sqrt{3}}{3+\sqrt{3}}\)
k)\(\left(\sqrt{28}-\sqrt{12}+\sqrt{7}\right).\sqrt{7}+2.\sqrt{21}\)
l)\(\frac{2.\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}\)
Ai đó giúp mình với ạ!
1) sqrt{12}-sqrt{27}+sqrt{3}
2)sqrt{252}-sqrt{700}+sqrt{1008}-sqrt{448}
3)3sqrt{112}-7sqrt{216}+4sqrt{54}-2sqrt{252}-3sqrt{96}
4)sqrt{18}-3sqrt{80}-2sqrt{50}+2sqrt{45}
5)6sqrt{12}-sqrt{20}-2sqrt{27}+sqrt{125}
6)2sqrt{18}-3sqrt{80}-5sqrt{147}+5sqrt{245}-3sqrt{98}
GIÚP MÌNH VỚI
Đọc tiếp
1) \(\sqrt{12}-\sqrt{27}+\sqrt{3}\)
2)\(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
3)\(3\sqrt{112}-7\sqrt{216}+4\sqrt{54}-2\sqrt{252}-3\sqrt{96}\)
4)\(\sqrt{18}-3\sqrt{80}-2\sqrt{50}+2\sqrt{45}\)
5)\(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
6)\(2\sqrt{18}-3\sqrt{80}-5\sqrt{147}+5\sqrt{245}-3\sqrt{98}\)
GIÚP MÌNH VỚI
50. √(98-16√3)
51. √(2-√3)
52. √(4+√15)
53. √(5-√21)
54. √(6-√35)
55. √(2+√3)
56. √(4-√15)
57. √(8-√55)
58. √(7+√33)
59. √(6+√35)
60. √(7-3√5)
1.
a) \(\sqrt{24-4\sqrt{5}}+\sqrt{14-6\sqrt{5}}\)
b)\(\sqrt{31-12\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
\(2\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}\)
Tính
a)\(\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\)
b)\(\sqrt{9-4\sqrt{5}}-\sqrt{9+4\sqrt{5}}\)
c) \(\sqrt{17-12\sqrt{2}}-\sqrt{24-8\sqrt{8}}\)
d)\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}\)
C/m các đẳng thức sau:
a) sqrt{21-6sqrt{6}} + sqrt{9+2sqrt{18}} - 2sqrt{6+3sqrt{3}} 0
b) dfrac{1}{sqrt{25}+sqrt{24}} + dfrac{1}{sqrt{24}+sqrt{23}} dfrac{1}{sqrt{23}+sqrt{22}} +...+ dfrac{1}{sqrt{2}+sqrt{1}} 4
c) dfrac{sqrt{2}+sqrt{3}+sqrt{4}}{sqrt{2}+sqrt{3}+sqrt{6}+sqrt{8}+4} sqrt{2} - 1
Mn giúp mk với !!!
Đọc tiếp
C/m các đẳng thức sau:
a) \(\sqrt{21-6\sqrt{6}}\) + \(\sqrt{9+2\sqrt{18}}\) - \(2\sqrt{6+3\sqrt{3}}\) = 0
b) \(\dfrac{1}{\sqrt{25}+\sqrt{24}}\) + \(\dfrac{1}{\sqrt{24}+\sqrt{23}}\) \(\dfrac{1}{\sqrt{23}+\sqrt{22}}\) +...+ \(\dfrac{1}{\sqrt{2}+\sqrt{1}}\) = 4
c) \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{4}}{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}\) = \(\sqrt{2}\) - 1
Mn giúp mk với !!!
thực hiện phép tính
a)sqrt{6+2sqrt{5}}-sqrt{62sqrt{5}}
b)sqrt{24-8sqrt{5}}+sqrt{9-4sqrt{5}}
c) sqrt{6-4sqrt{2}}+sqrt{22-12sqrt{2}}
d)sqrt{41+12sqrt{5}}-sqrt{46-6sqrt{ }5}
e)sqrt{17-12sqrt{2}}+sqrt{9+4sqrt{2}}
f)sqrt{17-12sqrt{2}}+sqrt{9+4sqrt{2}}
g) sqrt{43+24sqrt{3}}-sqrt{49-8sqrt{3}}
Đọc tiếp
thực hiện phép tính
a)\(\sqrt{6+2\sqrt{5}}-\sqrt{62\sqrt{5}}\)
b)\(\sqrt{24-8\sqrt{5}}+\sqrt{9-4\sqrt{5}}\)
c) \(\sqrt{6-4\sqrt{2}}+\sqrt{22-12\sqrt{2}}\)
d)\(\sqrt{41+12\sqrt{5}}-\sqrt{46-6\sqrt{ }5}\)
e)\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
f)\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
g) \(\sqrt{43+24\sqrt{3}}-\sqrt{49-8\sqrt{3}}\)
bài 1: thực hiện phép tính
1) 2√5−√125−√80+√605
2) √15−√216+√33−12√6
3) 10+2√10√5+√2 +81−√5
4) 2√8−√12√18−√48 −√5−√27√30−√162
5) 2√163 −3√127 −6√475
6) √2−√32+√3 −√2+√32−√3
GIÚP MÌNH VỚI M.N~~~!!!!!!!!! MÌNH ĐANG CẦN GẤP LẮM (T_T)