\(\frac{5}{-x^2+5x-6}+\frac{x+3}{2-x}=0\left(x\ne2,x\ne3\right)\)
\(\frac{5}{\left(2-x\right)\left(x-3\right)}+\frac{x+3}{2-x}=0\)
\(\Leftrightarrow5-\left(x+3\right)\left(x-3\right)=0\Leftrightarrow5-x^2+9=0\)
\(\Leftrightarrow4-x^2=0\Leftrightarrow\left[{}\begin{matrix}x=-2\left(tm\right)\\x=2\left(ktm\right)\end{matrix}\right.\)
Kl;........
(P/s: lần sau bn nhớ chép đề đúng ạ!!>>)
Giai phường trình sau:
a, \(3x^2+2x-1=0\) e, \(4x^2-12x+5=0\) i,\(2x^2+5x-3=0\)
b,\(x^2-5x+6=0\) f, \(2x^2+5x+3=0\) j,\(x^2+6x-16=0\)
c,\(x^2-3x+2=0\) g,\(x^2+x-2=0\)
d,\(2x^2-6x+1=0\) h, \(x^2-4x+3=0\)
Giải phương trình
1) 5(x - 3) - 4 = 2(x - 1)
2) 5(x - 3) - 2(x - 5) = x-2
3) 3(x - 2) - 14x = 2(3-) + 1
4) (x + 1)²+ 2x = x(x + 1) + 6
5) 3 - 4x(3 - 2x) = 8x² + x - 30
6) x²-x(5 - x) = 8
7) (x - 1)² - 36 = 0
8) (3x - 1)(4x - 3) + 2x(6x - 1) = 2(2x + 7)
9) (x - 2)² + 4(x - 3) =(x² + x - 3)
10) (x - 2)² – 2(x + 1) = (x - 1)(x - 2)
11) (x - 2)² + 3(x - 5) = x² + 3x - 3
12)(x - 3)² + (x + 3)² = 2 (x² +9)
13) (3x - 1)2 + (3x +1)² = 2(9x² + 4) + 1
14) (x - 1)(x - 2) + (2x + 1) = 5x²
a)\(x^4+\left(x-1\right)\left(3^{x^2}+2x-2\right)=0\)
b)\(\dfrac{x^2-3x+5}{x^2-4x+5}-\dfrac{x^2-5x+5}{x^2-6x+5}=\dfrac{-1}{4}\)
Giair phương trình sau:
a,\(2x^3+5x^2-3x=0\) b,\(2x^3+6x^2=x^2+3x\)
c,\(x^2+\left(x+2\right)\left(11x-7\right)=4\) d,\(\left(x-1\right)\left(x^2+5x-2\right)-\left(x^3-1\right)=0\)
e, \(x^3+1=x\left(x+1\right)\) f,\(x^3+x^2+x+1=0\)
g,\(x^3-3x^2+3x-1=0\) h,\(x^3-7x+6=0\)
i,\(x^6-x^2=0\) j,\(x^3-12=13x\)
k,\(-x^5+4x^4=-12x^3\) l, \(x^3=4x\)
a, \(\dfrac{x+2}{2x-4}-\dfrac{4x}{x^2-4}=0\)
b, \(\dfrac{x}{x-1}-\dfrac{5x-3}{x^2-1}=0\)
Bài 1:
a) 7x –12 = 5x + 3
b) 2(3x –5) –7(x + 1) = 2
c) (1 –3x)^2= (4x –3)^2
d) (2x + 3)(4x –2) –2(2x + 1)^2= 12
Bài 2:
Cho biểu thứcA = (5x –3y + 1)(7x + 2y –2)
a) Tìm x sao cho với y = 2 thì A = 0
b) Tìm y sao cho với x = -2 thì A = 0
giải pt sau:
a, 15x-3(3x-2)=45-5(2x-5)
b, x2-9+4(x-3)=0
c, \(\dfrac{1}{x-4}\)+\(\dfrac{x+2}{x+4}\)=\(\dfrac{5x-4}{x^2-16}\)
Phân tích các đa thức sau thành nhân tử:
A4=(x2-3x+5)2 + 7x(x2-3x +5) + 12x2
A5=2(x2+5x-2)2-7(x2+5x-2)(x3+3)+5(x2+3)2
A6=4(x2-15x+50)(x2-18x+72)-3x2
A7=x4-7x3+12x2-x-3
(2x-10).(5x+3)=0
x-2(x+1)>21x-24
