Question

5/ tìm x, biết :(x+2)(x+1)-(x-3)(x+5)=0

Answer 1

Ta có: (x+2)(x+1)-(x-3)(x+5) = 0

\(\Leftrightarrow\) x²+x+2x+2-x²-5x+3x+15 = 0

\(\Leftrightarrow\) x+17 = 0

\(\Leftrightarrow\) x = -17

Answer 2

(x+2)(x+1)-(x-3)(x+5)=0

<=>x\(^2\)+3x+2-(\(x^2\)+2x-15)=0

<=>x\(^2\)+3x+2-x\(^2\)-2x+15=0

<=>x+17=0

<=>x=-17

Vậy x=-17

Answer 3

(X+2)(X+1)-(X-3)(X+5)=0

=>X²+X+2X+2-X²-5X+3X+15=0

=>X+17=0

=>X=-17