Question

(4x-1)(x-3)-2x+6=0

Answer 1

`(4x-1)(x-3)-2x+6=0`

`(4x-1)(x-3)-2(x-3)=0`

`<=> (x-3).(4x-3)=0`

`<=>` \(\left[{}\begin{matrix}x-3=0\\4x-3=0\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}x=0+3=3\\4x=0+3=3\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}x=3\\x=\dfrac{3}{4}\end{matrix}\right.\)

Vậy \(S=\left\{3;\dfrac{3}{4}\right\}\)

Answer 2

=>(4x-1)(x-3)-2(x-3)=0

=>(x-3)(4x-3)=0

=>x=3 hoặc x=3/4