\(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
\(\Rightarrow x=\dfrac{3}{5}+\dfrac{4}{7}=\dfrac{41}{35}\)
`-4/7-x=3/5-2x`
`<=>-x+2x=3/5+4/7`
`<=>x=7/5`
Vậy `x=7/5`
\(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
\(\Leftrightarrow x=\dfrac{3}{5}+\dfrac{4}{7}=\dfrac{41}{35}\)