(*)\(\dfrac{7}{4}\cdot x+\dfrac{3}{2}=\dfrac{-2}{5}\)
=>\(x=\left(\dfrac{-2}{5}-\dfrac{3}{2}\right):\dfrac{7}{4}\)
=>\(x=\dfrac{-38}{35}\)
(*) (5x-1)(2x-1/3)=0
=>5x-1=0 hoặc 2x-1/3=0
5x=1 2x=1/3
x=1/5 x=1/6
Vậy x=1/5 hoặc x=1/6
*\(\dfrac{7}{4}.x+\dfrac{3}{2}=\dfrac{-2}{5}\)
\(\Rightarrow\dfrac{7}{4}.x=\dfrac{-2}{5}-\dfrac{3}{2}=\dfrac{-4}{10}-\dfrac{15}{10}=\dfrac{-19}{10}\)
\(\Rightarrow x=\dfrac{-19}{10}:\dfrac{7}{4}=\dfrac{-19}{10}.\dfrac{4}{7}=\dfrac{-38}{35}\)
*\(\left(5x-1\right)\left(2x-\dfrac{1}{3}\right)=0\Rightarrow5x-1=0\) hoặc \(2x-\dfrac{1}{3}=0\)
+Với \(5x-1=0\Rightarrow5x=0+1=1\)
_________________\(x=1:5=\dfrac{1}{5}\)
+Với \(2x-\dfrac{1}{3}=0\Rightarrow2x=0+\dfrac{1}{3}=\dfrac{1}{3}\)
_________________\(x=\dfrac{1}{3}:2=\dfrac{1}{3}.\dfrac{1}{2}=\dfrac{1}{6}\)
