4^5 . 3^2 + 2^10 - 2^3 . 30
=1024 . 9 + 1024 - 8 . 30
=1024 . 9 + 1024 . 1 - 8 . 30
=1024 . ( 9+1 ) - 240
=1024 . 10 - 240
=10240 - 240
=10000
4^5 . 3^2 + 2^10 - 2^3 . 30
=1024 . 9 + 1024 - 8 . 30
=1024 . 9 + 1024 . 1 - 8 . 30
=1024 . ( 9+1 ) - 240
=1024 . 10 - 240
=10240 - 240
=10000
\(\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\frac{4^4}{3\cdot5}\cdot\cdot\cdot\frac{50^2}{49\cdot51}\)
\(E=\frac{2}{1\cdot3}\cdot\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{97\cdot99}\)
\(A=\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}\cdot.........\cdot\frac{1}{99.100}\)
a, \(P=\dfrac{1+2}{1^2\cdot2^2}+\dfrac{2+3}{2^2\cdot3^2}+...+\dfrac{9+10}{9^2\cdot10^2}\)
Chứng minh rằng: \(P< 1\)
b, \(Q=\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}\)
Chứng minh rằng: \(Q< \dfrac{1}{2}\)
__________
- Mình cần gấp. Giúp mình nhé.
Tính : \(A=\frac{2,5-4\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
Rút gọn \(B=\frac{3^9-2^3.3^7+2^{10}.3^2-2^{13}}{3^{10}-2^2.3^7+2^{10}.3^3-2^{12}}\)
2(4x-3)-3(x+5)+4(x-10)= 5(x+2)
1, Tìm x
a, (3x^2-50)^2=5^4
2, Rút gọn
a, (3^4-3^3)^4/27^3
b, 25^3/(5^5-5^3)^2
3, Thực hiện phép tính
a, (-1/3)^2 . 9 - (1/2)^3 .16 +(2:1/2^2)
b, (3/7)^10 . (7^5)^9 : (9/25)^5
c, (0,25)^5 . 2^11 : (1/3)^2
1) ( -213) + 186 + ( - 14 ) + 217 + 54 + ( - 49 )
2 ) - 38 . ( 25 - 4 ) + 25 . ( -4 + 38 )
3) -39 . ( 5 - 99 ) + 99 . ( 10 - 39 )
4 ) 1+ 3-5-7+9+ 11 - ....- 397 - 399
5) 1+ 2 + 2^2 + ... + 2 ^ 100
6) 3^102 - 3 ^ 100 - 3 ^ 98 -...3 ^2 - 3 ^0
\(\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}^{ }-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)