\(\left(3x-2\right)\left(4x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{matrix}\right.\)
vậy \(x=\dfrac{2}{3}\) hoặc \(x=-\dfrac{5}{4}\)
(3x-2)(4x+5)=0
\(\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Chúc bạn học tốt nhé
(3x-2)(4x+5)=0
\(\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{matrix}\right.\)
Cái kia sai nha
Lộn :)
\(\left(3x-2\right) \left(4x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{-5}{4}\end{matrix}\right.\)
