3(x - 1)2 - 3x(x - 5) - 2 = 0
3(x2 - 2x + 1) - (3x2 - 15x) - 2 = 0
3x2 - 6x + 3 - 3x2 + 15x - 2 = 0
9x + 1 = 0
\(\Rightarrow\) 9x = -1
\(\Rightarrow\) x = \(\dfrac{-1}{9}\)
vậy x = \(\dfrac{-1}{9}\)
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\(3\left(x-1\right)^2-3x\left(x-5\right)-2=0\)
\(3\left(x^2-2x+1\right)-3x^2+15x-2=0\)
\(3x^2-6x+3-3x^2+15x-2=0\)
\(9x+1=0\)
\(x=\dfrac{1}{9}\)
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