\(\left(3x-1\right)\left(9x^2+3x+1\right)=\left(3x\right)^3-1=27x^3-1\)
\(\left(3x-1\right)\left(9x^2+3x+1\right)=27x^3-1\)
(1-3x)2 - (x-2)(9x+1) = (3x-4)(3x+4) - 9(x+3)2
Tìm x biết
(1-3x)2 - (x-2)(9x+1) = (3x-4)(3x+4) - 9(x+3)2
Tìm x biết
(1-3x)2 - (x-2)(9x+1) = (3x-4)(3x+4) - 9(x+3)2
Tìm x biết
(1-3x)2 - (x-2)(9x+1) = (3x-4)(3x+4) - 9(x+3)2
Giúp mình đi :))
tìm x :
a) (x+2)^2-25=0
b) x(9x-1)-(3x+5)(3x-5)=1
ai giúp mình câu này đc ko mình cần gấp (ko chắc)
\(a,4x-8/2x^2+1=0 b,x2-x-6/x-3=0 c,x+5/3x-6-1/2=2x-3/2x-4 d,12/1-9x^2=1-3x/1+3x-1+3x/1-3x\)
\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\\ \left(\frac{3x}{1-3n}+\frac{2n}{3x+1}\right):\left(\frac{6x^2+10x}{1-6x+9x^2}\right)\\ \left(\frac{9}{x^3-9n}+\frac{1}{x+3}\right):\left(\frac{x}{3n+9}\right)\)
3 (2x - 1) .(3x -1) - (2x-3) .(9x-1) = -1
chứng minh biểu thức sau khoomg phụ thuộc vào biến x
A= (2x- 1)(x2+x -1)-(x-5)2-2(x-1)(x2-x+1)-7(x-2)
B+(x3-3x+5)2+2(x2-3x+5)(1+3x-x2)+(1-x2+3x)2
C=(3x-2)(9x2+6x+4)-27(x+6)(x2-6x+36)
