\(=\dfrac{3^9}{3^{12}}\cdot\dfrac{2^8}{2^6}=\dfrac{1}{27}\cdot4=\dfrac{4}{27}\)
\(\dfrac{3^9.2^8}{3^{12}.2^6}=\dfrac{3^9.2^6.2^2}{3^9.3^3.2^6}=\dfrac{2^2}{3^3}=\dfrac{4}{27}\)
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