Question

3) phân tích thành nhân tử

a) 3x⁴+4x²+1

b) x⁴+3x²-4

c) 4x⁴-37x²+9

d) (x²+x)²+4(x²+x)-12

e) x.(x+4) (x+6) (x+10)+128 gải giúp mình cần gắp trưa học òi

Answer 1

a. \(3x^4+4x^2+1=\left(3x^2+1\right)\left(x^2+1\right)\)

b. \(x^4+3x^2-4=\left(x^2-1\right)\left(x^2+4\right)\)

c. \(4x^4-37x^2+9=\left(x^2-9\right)\left(4x^2-1\right)\)

d. \(\left(x^2+x\right)^2+4\left(x^2+x\right)-12=x^4+2x^3+x^2+4x^2+4x-12=x^4+2x^3+5x^2+4x-12=\left(x-1\right)\left(x^3+3x^2+8x+12\right)=\left(x-1\right)\left(x+2\right)\left(x^2-x+6\right)\)

e. \(x\left(x+4\right)\left(x+6\right)\left(x+10\right)+128=x^4+20x^3+124x^2+240x+128=\left(x^2+10x+8\right)\left(x^2+10x+16\right)\)

Answer 2

a)3x^4+4x^2+1

= x² (3x² + 4)+1

b) x⁴+3x²-4

= x² ( x² + 3 )-4

c) 4x⁴-37x²+9

= x² ( 4x² - 37 ) + 9

d) (x²+x)²+4(x²+x)-12

= ( x² + x )[( x²+x) + 4]-12

e) x.(x+4) (x+6) (x+10)+128

= x . (x + 2) (2+3+5)+128

Answer 3

bn ngứa à mk ko gải cho đâu