=>2x^2-4x+3x-6=6x-3x^2+10-5x
=>2x^2-x-6=-3x^2+x+10
=>5x^2-2x-16=0
=>x=2; x=-8/5
=>2x^2-4x+3x-6=6x-3x^2+10-5x
=>2x^2-x-6=-3x^2+x+10
=>5x^2-2x-16=0
=>x=2; x=-8/5
Làm bài 21 phần e và f
\(\left(2x-5\right)^2\)- \(\left(x+2\right)^2\) = 0
\(x^2-x-\left(3x-3\right)=0\)
Giải phương trình :
a)(2x-5)^3-(3x-4)^x+(x+1)^3=0
b)(x-1)^3+(2x-3)^3+(3x-5)^3 - 3(x-1)(2x-3)(3x-5) = 0
c)(x^2+3x-4)^3 + (3x^2+7x+4)^3 = (4x^2+10x)^3
1/(2x-1)(3x+2)(5-x)=0
2/(2x+5)(x-4)=(x-5)(4-x)
3/16x^2-8x+1=4(x+3)(4x-1)
4/27x^2(x+3)-12(×^2+3x)=0
5/2(9x^2+6x+1)=(3x+1)(x-2)
6/(2x-1)^2=49
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
a) (2x+1)^2-2x-1=2b) (x^2-3x)^2+5(x^2-3x)+6=0c) (x^2-x-1)(x^2-x)-2=0d) (5-2x)^2+4x-10=8e) (x^2+2x+3)(x^2+2x+1)=3f) x(x-1)(x^2-x+1)-6=0
Bài 1: giải các pt sau:
1,(x-1)^2-(x+1)^2=2(x+3)
2,(2x-1)^2-(2x+1)^2=4(x-3)
3,(2x+3)^2-(2x+3).(2x-4)=-(x-2)^2
4,8x^3-(x+1)^3=3x-3
5,(3x-2).(9x^2+6x+4)-(3x+1).(9x^2-3x+1)=(2x+1).(2x-1)-4x(x-3)
Giải phương trình:
a) \(\dfrac{x^2-x-6}{x-3}=0\)
b) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
c) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
d) \(\dfrac{x+5}{x-1}=\dfrac{x+1}{x-3}-\dfrac{8}{x^2-4x+3}\)
e) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)Thể loại truyện
Giải phương trình:
4. (2x+7)(x+3)2(2x+5)=18
5. (x2-3x+2)(2x-3)(2x-5)=30
6. (x2+3x+2)(x2+7x+12)=24
Bài1:Giải phương trình:
a,(5-x)(3-2x)(3x+4)=0
b,(2x-1)(3x+2)(5-x)=0
c,(2x-1)(x-3)(x+7)=0
Giúp mình với :)
d,(3-2x)(6x+4)(5-8x)=0