(2x+3)2+(2x-3)2-(2x+3)(4x-6)+xy
=> \(\left(4x^2+12x+9\right)+\left(4x^{ }-12x+9\right)-\left(2x+3\right).2.\left(2x-3\right)+xy\)
=>\(4x^2+12x+9+4x^2-12x+9-\left(2x+3\right)\left(2x-3\right).2+xy\)
=>\(8x^2+18-\left(4x^2-9\right).2+xy\)
=> \(8x^2+18-8x^2-18+xy\)\(=\left(8x^2-8x^2\right)+\left(18-18\right)+xy\)
= xy
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(2x+3)\(^2\) +(2x-3)\(^2\) -(2x+3)(4x-6)+xy
= (2x+3)\(^2\) - 2 (2x-3)(2x+3)+(2x-3)\(^2\) +xy
= (2x+3-2x+3)\(^2\) +xy = 36+xy = ?
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