`(2x)/3+2/3=x-1/6`
`=>x-(2x)/3=2/3+1/6`
`=>x/3=5/6`
`=>x=5/2`
Vậy `x=5/2.`
Ta có: \(\dfrac{2x}{3}+\dfrac{2}{3}=x-\dfrac{1}{6}\)
\(\Leftrightarrow\dfrac{2}{3}x-x=\dfrac{-1}{6}-\dfrac{2}{3}=\dfrac{-5}{6}\)
\(\Leftrightarrow\dfrac{-1}{3}x=\dfrac{-5}{6}\)
hay \(x=\dfrac{5}{2}\)