=>(2x+1)^4*[(2x+1)^2-1]=0
=>2x(2x+1)^4*(2x+2)=0
hay \(x\in\left\{0;-\dfrac{1}{2};-1\right\}\)
\(\left(2x+1\right)^6=\left(2x+1\right)^4\)
\(\left(2x+1\right)^6-\left(2x+1\right)^4=0\)
\(\left(2x+1\right)^4.\left(2x+1\right)^2-\left(2x+1\right)^4=0\)
\(\left(2x+1\right)^4.\left[4x^2+4x\right]=0\)
\(\left(2x+1\right).4x\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=-1\\x=0\\x=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=0\\x=-1\end{matrix}\right.\)