Tìm x, biết:
(2x + 1)3 = -8
(2x + 1) = \(\sqrt[3]{-8}\) = -2
2x = (-2) + (-1)
x = (-3) : 2
x = \(\dfrac{-3}{2}\)
Vậy x = \(\dfrac{-3}{2}\);
(2x+1)^3=-8
(2x+1)^3=(-2)^3
suy ra: 2x+1=-2
2x=-2 -1
2x=-3
x=-3:2
x= \(\dfrac{-3}{2}\)
Tìm x, biết:
(2x + 1)3 = -8
(2x + 1) = \(\sqrt[3]{-8}\) = -2
2x = (-2) + (-1)
x = (-3) : 2
x = \(\dfrac{-3}{2}\)
Vậy x = \(\dfrac{-3}{2}\);
(2x+1)^3=-8
(2x+1)^3=(-2)^3
suy ra: 2x+1=-2
2x=-2 -1
2x=-3
x=-3:2
x= \(\dfrac{-3}{2}\)
a) 3^2x-1=243
b) 3^x+1=9^x
c) (4/7-1/2x)^3=-8/34
3/2 . x + 3/7 = -4/5
-11/12 . x + 0.25 =5/6
(x - 2)2 =1
(2x - 1)3 = -8
tính giá trị biểu thức 4x-2/3 biết 2x-1/5=8
(2x-1)^6=(2x-1)^8
tím x biết: \(\left|2x+3\right|+\left|2x-1\right|=\dfrac{8}{3\left(x+1\right)^2+2}\)
Mn giúp mk vs ạ!!! Ai lm đúng mk sẽ tick cho
Thanks mn nhiều......
/2x-1/+/1-2x/=8
/ là GTTĐ
Tìm x :
(2,5-3x):\(1\dfrac{2}{3}\)=\(\left(\dfrac{8}{5}+2x\right):\left(-\dfrac{8}{17}\right)\)
Tìm x:
a) \(\dfrac{3}{2}\) |2+x| = \(\dfrac{5}{4}\)
b) (2x + 1)3 = -8
1. tìm x
a, 2x - \(\dfrac{1}{2}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{9}\)
b, x\(^2\) - 2 = 0
2. Cho
A = \(\dfrac{1,11+0,19-13.2}{2,06+0,54}\) - \(\left(\dfrac{1}{2}+\dfrac{1}{4}\right)\) : 2
B = \(\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right)\) : \(2\dfrac{23}{26}\)
a, Rút gọn A, B
b, Tìm x ϵ Z để A < x < B