Ta có: \(\left(2x-3\right)^2=25\)
\(\Rightarrow\left(2x-3\right)^2=5^2\)
\(\Rightarrow2x-3=5\)
\(\Rightarrow2x=5+3=8\)
\(\Rightarrow x=\frac{8}{2}=4\)
Vậy: \(x=4\)
ta có:(2x-3)^2=5^(2
nen (2x-3)=5
2x=5+3
2x=8
x=8/2
x=4
Ta có: (2x-3)2=25
=> 2x-3 = \(\pm5\)
=>\(\left[{}\begin{matrix}2x-3=5\\2x-3=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)
Vậy x\(\in\left\{4;-1\right\}\)