`#3107.101107`
`(2x - 3)^2 = 36`
`=> (2x - 3)^2 = (+-6)^2`
`=>`\(\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=9\\2x=-3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
Vậy, `x \in {-3/2; 9/2}.`
\(\left(2x-3\right)^2=36\)
\(\Rightarrow\left(2x-3\right)^2=\left(\pm6\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=9\\2x=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
Vậy: ...