\(\left(2x-1\right)\left(x-3\right)=-2x+2\\ \Leftrightarrow2x^2-x-6x+3+2x-2=0\\ \Leftrightarrow2x^2-5x+1=0\)
\(\Delta=\left(-5\right)^2-4.2.1=25-8=17>0\)
\(x_1=\dfrac{-\left(-5\right)+\sqrt{17}}{2.2}=\dfrac{5+\sqrt{17}}{4}\)
\(x_1=\dfrac{-\left(-5\right)-\sqrt{17}}{2.2}=\dfrac{5-\sqrt{17}}{4}\)