\(\left(2x-1\right)^2=25\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(2x-1\right)^2=5^2\\\left(2x-1\right)^2=\left(-5\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Vậy ..
\(\left(2x-1\right)^2=25\\ \Leftrightarrow\left(2x-1\right)^2=\left(\pm5\right)^2\\ \Rightarrow\left\{{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2x=6\\2x=-4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
(2x-1)2 = 25
\(\Rightarrow\) 2x-1=25 hoặc 2x-1=-25
th1
2x-1=25
2x = 26
x = \(\dfrac{26}{2}\)
x = 13
th2
2x-1=-25
2x=-24
x= \(\dfrac{-24}{2}\)
x = -12
vậy x = 13 ; x=-12