\(\Leftrightarrow\left(2x-1\right)\left(2x-1+2-x\right)=0\Leftrightarrow\left(2x-1\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=0,5\left(thoaman\right)\\x+1=0\Leftrightarrow x=-1\left(thoaman\right)\end{matrix}\right..Vậy:x\in\left\{\frac{1}{2};-1\right\}\)
5,\(\dfrac{x^2-5x-4}{8}\)=\(\dfrac{x+1}{2}\)+\(\dfrac{x^2-10x}{9}\)
6,(x+3)(x-3)=(x-1)(9-x)
7,(x-1)\(^2\)=9(x^2+2x+1)
8,(x^2-5x+8)\(^2\)-(5x-17)\(^2\)
giup em voi a
(3x-1)/(2-5x)<0
(3x-2)/(1-2x)<1
(2x(3x-5))/(x2+1)<0
(x-3(2x-1))/(2x-3)>0
giúp rồi minh tich cho nha!!!
chiều mik học rồi
1. giải phương trình.
a. (2x+1)(x-1)=0
b. \(\left(x+\frac{2}{3}\right)\left(x-\frac{1}{2}\right)\) (x+2020)=0
c. (3x-1)(2x-3)(2x-3)(x+5)=0
d. 3x-15=2x(x-5)
e. x2-2x+1=0
f. x2+x+\(\frac{1}{4}\) =0
g. x2-3x-4=0
h. (x+1)(x+4)=(2-x)(x+2)
Giải các phương trình sau:
a/ (2x+1)(x2+2)=0
b/ (x2+x+1)(6-2x)=0
c/ (x-5)(3-2x)(3x+4)=0
d/ (x2+4)(7x-3)=0
e/ (8x-4)=(x2+x+2)
f/ (2x-1)(3x+2)(5-x)
Gải phương trình;
a) 2x(x - 3) + 5(x - 3) = 0 b) (2 - 3x)(x + 11) = (3x - 2)( 2 - 5x)
c) ( 2x + 1)( 3x - 2) = (5x - 8)( 2x + 1) d) ( x - 1)( 2x - 1) = x(1 - x)
e) 0,5x (x - 3) = (x - 3)( 1,5x - 1) f) (x +2)(3 - 4x) = x2 + 4x = 4
g) ( 2x2 +1)(4x - 3 ) = ( x - 12)( 2x2 + 1) h) 2x( x - 1) = x2 - 1
Bài 8:Giải cácphương trình sau.
a) (3x – 2)(4x + 5) = 0 b) 2x(x – 3) + 5(x – 3) = 0
c) (2x + 1)(3x – 2) = (5x – 8)(2x + 1) d) 3x – 15 = 2x(x – 5)
e) x(2x – 9) = 3x(x – 5) f) (x + 2)(3 – 4x) = x2 + 4x + 4
g) (x –\(\sqrt{2}\)) + 3(x2 – 2) = 0 h) (2x – 5)2 – (x + 2)2 = 0
i) 2x3 + 5x2 – 3x = 0 k) 2x2 – 6x + 1 = 0
Tìm x
a, (1-2x)(1+2x)+(2x+3)2=34
b, (2x-3)2+(3-2x)(x-1)=0
3x + 1 = x – 3
Phương trình nào sau đây có một nghiệm : x^2-3x=0 2x+1=1+2x x(x-1)=0 (x+2)(x^2+1)=0giải pt
a , (x2-4x)2+(x-2)2=10
b (2x+1)(x+1)2(2x+3)-18=0
c (2x+1)2(4x+1)(4x+3)-18=0
