\(\dfrac{2^{4-x}}{16^5}=32^6\)
\(\Leftrightarrow2^{4-x}=16^5.32^6\)
\(\Rightarrow2^{4-x}=\left(2^4\right)^5.\left(2^5\right)^6\)
\(\Rightarrow2^{4-x}=2^{20}.2^{30}\)
\(\Rightarrow2^{4-x}=2^{50}\)
\(\Rightarrow4-x=50\)
\(\Rightarrow x=-46\)
Vậy...
\(\dfrac{2^{4-x}}{16^5}=32^6\Rightarrow\dfrac{2^{4-x}}{2^{20}}=2^{30}\Rightarrow2^{4-x}=2^{50}\Rightarrow x=-46\)