Question

2/3x-1/2x-2-x-4/6x-6x^2

Answer 1

đề bài bn ghi rõ ra dc ko ạ

Answer 2

(2 phần 3x)- (1 phần 2x-2)-(x-4 phần 6x-6x^2)

Answer 3

\(\dfrac{2}{3x}-\dfrac{1}{2x-2}-\dfrac{x-4}{6x-6x^2}\)

\(=\dfrac{2}{3x}-\dfrac{1}{2\left(x-1\right)}+\dfrac{x-4}{6x\left(x-1\right)}\)

\(=\dfrac{4\left(x-1\right)-3x+x-4}{6x\left(x-1\right)}=\dfrac{4x-4-2x-4}{6x\left(x-1\right)}\)

\(=\dfrac{2x-8}{6x\left(x-1\right)}=\dfrac{x-4}{3x\left(x-1\right)}\)

Answer 4

\(\dfrac{2}{3x}\)- \(\dfrac{1}{2x}\)- 2 - x -\(\dfrac{4}{6x}\)- 6x² 

ko bt cs đúng đề bài ko