Bài 8: Rút gọn biểu thức chứa căn bậc hai
Các câu hỏi tương tự
1 .
a)Afrac{2}{2sqrt[3]{2}+2+sqrt[3]{4}}
b)Bfrac{6}{2sqrt[3]{2}-2+sqrt[3]{4}}
c)Cfrac{2}{sqrt[3]{4}+sqrt[3]{2}+2}
2 .
a)Asqrt{sqrt{5}-sqrt{3-sqrt{29-12sqrt{5}}}}
b)Bfrac{left(5+2sqrt{6}right).left(49-20sqrt{6}right).sqrt{5-2sqrt{6}}}{9sqrt{3}-11sqrt{2}}
c)Csqrt{4+sqrt{5sqrt{3}+5sqrt{48-10sqrt{7}+4sqrt{3}}}}
d)D(left(sqrt{3}-1right).sqrt{6+2sqrt{2}.sqrt{3-sqrt{sqrt{2}+sqrt{12}+sqrt{18-sqrt{128}}}}}
Đọc tiếp
1 .
a)\(A=\frac{2}{2\sqrt[3]{2}+2+\sqrt[3]{4}}\)
b)\(B=\frac{6}{2\sqrt[3]{2}-2+\sqrt[3]{4}}\)
c)C=\(\frac{2}{\sqrt[3]{4}+\sqrt[3]{2}+2}\)
2 .
a)\(A=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b)\(B=\frac{\left(5+2\sqrt{6}\right).\left(49-20\sqrt{6}\right).\sqrt{5-2\sqrt{6}}}{9\sqrt{3}-11\sqrt{2}}\)
c)C=\(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7}+4\sqrt{3}}}}\)
d)D=(\(\left(\sqrt{3}-1\right).\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)
Tính :
a) \(\left(5+4\sqrt{2}\right)\left(3+2\sqrt{1+\sqrt{2}}\right)\left(3-2\sqrt{1+\sqrt{2}}\right)\)
b) \(\dfrac{3\sqrt{8}-2\sqrt{12}+\sqrt{40}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
1. Rút gọn biểu thức sau:
a, \(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
b, (\(\sqrt{3}-1\)) \(\sqrt{6+2\sqrt{2}\sqrt[]{3}-\sqrt{\sqrt{2}}+\sqrt{12}+\sqrt{18-128}}\)
5 câu:1) dfrac{sqrt{3}+sqrt{2}}{sqrt{6}+2}-dfrac{sqrt{3}-sqrt{2}}{sqrt{6}-2}2) dfrac{3}{sqrt{5}-sqrt{2}}-dfrac{2}{2-sqrt{2}}+dfrac{1}{sqrt{3}+sqrt{2}}3) dfrac{12}{sqrt{5}+1}-dfrac{4}{sqrt{5}+2}+dfrac{20}{3+sqrt{5}}4) dfrac{5}{3-sqrt{7}}-dfrac{2}{sqrt{2}+sqrt{3}}-dfrac{1}{sqrt{2}-1}5) dfrac{sqrt{12}-6}{sqrt{8}-sqrt{24}}-dfrac{3+sqrt{3}}{sqrt{3}}-dfrac{4}{sqrt{7}-1}
Đọc tiếp
5 câu:
1) \(\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{6}+2}-\dfrac{\sqrt{3}-\sqrt{2}}{\sqrt{6}-2}\)
2) \(\dfrac{3}{\sqrt{5}-\sqrt{2}}-\dfrac{2}{2-\sqrt{2}}+\dfrac{1}{\sqrt{3}+\sqrt{2}}\)
3) \(\dfrac{12}{\sqrt{5}+1}-\dfrac{4}{\sqrt{5}+2}+\dfrac{20}{3+\sqrt{5}}\)
4) \(\dfrac{5}{3-\sqrt{7}}-\dfrac{2}{\sqrt{2}+\sqrt{3}}-\dfrac{1}{\sqrt{2}-1}\)
5) \(\dfrac{\sqrt{12}-6}{\sqrt{8}-\sqrt{24}}-\dfrac{3+\sqrt{3}}{\sqrt{3}}-\dfrac{4}{\sqrt{7}-1}\)
tính1.left(sqrt{15}-2sqrt{3}right)^2+12sqrt{5}2.3sqrt{2}left(4-sqrt{2}right)+3left(1-2sqrt{2}right)^23.dfrac{1}{2}left(sqrt{6}+sqrt{5}right)^2-dfrac{1}{4}sqrt{120}-sqrt{dfrac{15}{2}}4.left(sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}right)^25.left(sqrt{sqrt{14}+sqrt{5}}+sqrt{sqrt{14}-sqrt{5}}right)^26.left(sqrt{3}+1right)^3-left(sqrt{3}-1right)^37.left(sqrt{2}+1right)^3-left(sqrt{2}-1right)^38.sqrt{13-sqrt{160}}-sqrt{53+4sqrt{90}}9.sqrt{3-sqrt{5}}+sqrt{3+sqrt{5}}
Đọc tiếp
tính
1.\(\left(\sqrt{15}-2\sqrt{3}\right)^2+12\sqrt{5}\)
2.\(3\sqrt{2}\left(4-\sqrt{2}\right)+3\left(1-2\sqrt{2}\right)^2\)
3.\(\dfrac{1}{2}\left(\sqrt{6}+\sqrt{5}\right)^2-\dfrac{1}{4}\sqrt{120}-\sqrt{\dfrac{15}{2}}\)
4.\(\left(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}\right)^2\)
5.\(\left(\sqrt{\sqrt{14}+\sqrt{5}}+\sqrt{\sqrt{14}-\sqrt{5}}\right)^2\)
6.\(\left(\sqrt{3}+1\right)^3-\left(\sqrt{3}-1\right)^3\)
7.\(\left(\sqrt{2}+1\right)^3-\left(\sqrt{2}-1\right)^3\)
8.\(\sqrt{13-\sqrt{160}}-\sqrt{53+4\sqrt{90}}\)
9.\(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
Rút gọn biểu thức
a, 3 căn 18 - căn 32 +4 căn 2 +căn 162
b, 2 căn 48 - 4 căn 27+ căn 75 + căn 12
c, căn 21+8 căn 5 + căn 21 -8 căn 5
d,(căn 14 - căn 7/căn 2-1 + căn 15 - căn 5/ căn 3-1 )÷1/căn 7- căn 5
Giải bài đầy đủ giùm mình, đừng viết tắt.1) dfrac{1}{3-2sqrt{2}}-dfrac{1}{3+2sqrt{2}}2)dfrac{1}{sqrt{2}-sqrt{3}}-dfrac{3}{sqrt{18}+2sqrt{3}}3)dfrac{2}{sqrt{5}-2}+dfrac{-2}{sqrt{5}+2}4)dfrac{3}{1-sqrt{2}}+dfrac{sqrt{2}-1}{sqrt{2}+1}5)dfrac{sqrt{7}+sqrt{5}}{sqrt{7}-sqrt{5}}-dfrac{sqrt{7}-sqrt{5}}{sqrt{7}+sqrt{5}}
Đọc tiếp
Giải bài đầy đủ giùm mình, đừng viết tắt.
1) \(\dfrac{1}{3-2\sqrt{2}}-\dfrac{1}{3+2\sqrt{2}}\)
2)\(\dfrac{1}{\sqrt{2}-\sqrt{3}}-\dfrac{3}{\sqrt{18}+2\sqrt{3}}\)
3)\(\dfrac{2}{\sqrt{5}-2}+\dfrac{-2}{\sqrt{5}+2}\)
4)\(\dfrac{3}{1-\sqrt{2}}+\dfrac{\sqrt{2}-1}{\sqrt{2}+1}\)
5)\(\dfrac{\sqrt{7}+\sqrt{5}}{\sqrt{7}-\sqrt{5}}-\dfrac{\sqrt{7}-\sqrt{5}}{\sqrt{7}+\sqrt{5}}\)
Rút gọn các bt sau
A√(5-√21) +√(5+√21)
B[(√15 -√5)/(√3 -1)]+[(5-2√2)/(2√5 -4)]
C {1+[(11-√11)/(1-√11)]}×{[(11+√11)/(1+√11)]+1}
D[√2/(√2-√3)]-[√2/(√2+√3)]
E[1/(√2 -√3)]×√[(3√2 -2√3)/(3√2+2√3)]
F√(6-2√2 +2√3 -2√6 )
G√[(6+2√5-√(29-12√5)]
H1/√3 +1/3√2 +1/√3×[(5/12)×(1/√6)]
I(√2+1)×(√2^2 +1)×(√2^4 +1)×(√2^8 +1)(√2^16 +1)
K1/(√2 +√3)+1/(√3 +√4) +1/(√4 +√5)+.....+1/(√2009 +√2010)
L{(4+√7)/[3√2 +√(4+√7)]}+{(4-√7)/[3√2 -√(4-√7)]}
Hỡi các cao nhân giúp em với em xin hậu tạ
Đọc tiếp
Rút gọn các bt sau
A=√(5-√21) +√(5+√21)
B=[(√15 -√5)/(√3 -1)]+[(5-2√2)/(2√5 -4)]
C= {1+[(11-√11)/(1-√11)]}×{[(11+√11)/(1+√11)]+1}
D=[√2/(√2-√3)]-[√2/(√2+√3)]
E=[1/(√2 -√3)]×√[(3√2 -2√3)/(3√2+2√3)]
F=√(6-2√2 +2√3 -2√6 )
G=√[(6+2√5-√(29-12√5)]
H=1/√3 +1/3√2 +1/√3×[(5/12)×(1/√6)]
I=(√2+1)×(√2^2 +1)×(√2^4 +1)×(√2^8 +1)(√2^16 +1)
K=1/(√2 +√3)+1/(√3 +√4) +1/(√4 +√5)+.....+1/(√2009 +√2010)
L={(4+√7)/[3√2 +√(4+√7)]}+{(4-√7)/[3√2 -√(4-√7)]}
Hỡi các cao nhân giúp em với em xin hậu tạ
1. √(9-4√5) - √(14+6√5)
2.(3√2+√10) +√(28-12√5)
3.√(4+2√3)× √(√3 - 1) 2
4. √(13-√160)-√(53+4√60)