18-6\(\sqrt{10}\)1=8-360=-342
19+8\(\sqrt{3}\)=19+192=211
27+10\(\sqrt{2}\)=27+200=227
28+12\(\sqrt{2}\)=28+288=316
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Bài 2: Căn thức bậc hai và hằng đẳng thức căn bậc hai của bình phương
Các câu hỏi tương tự
Rút gọn\(B=\frac{3\sqrt{8}+2\sqrt{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\\ C=\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
a,\(\left(\sqrt{2}+2\right)\sqrt{2}-2\sqrt{2}\)
b, \(\sqrt{(\sqrt{5}-\sqrt{10})^2}-\sqrt{10(\sqrt{2+1)}^2}\)
c,\((\sqrt{2}+\sqrt{3})^2.\sqrt{49-20\sqrt{6}}\)
d, \(\dfrac{2}{\sqrt{8-\sqrt{60}}}-\sqrt{\dfrac{\sqrt{18}+\sqrt{27}}{\sqrt{3}+\sqrt{2}}}\)
1.tính
a) \(\sqrt{3-2\sqrt{2}}\)
b)\(\sqrt{28+10\sqrt{3}}\)
c)\(\sqrt{14+6\sqrt{5}}\)
d)\(\sqrt{13-4\sqrt{3}}\)
2.tính
a)\(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}\)
b)\(\sqrt{18+8\sqrt{2}}-\sqrt{18-8\sqrt{2}}\)
Tínha.sqrt{8+2sqrt{5}} b.sqrt{10-2sqrt[]{5}} c.sqrt{5+sqrt{24}} d.sqrt{12-sqrt{140}} e.sqrt{14+2sqrt{5}} f. sqrt{8-sqrt{28}} g.sqrt{23-4sqrt{15}} h.sqrt{9+4sqrt{2}} giúp mik vs mai mik nộp rồi,cảm ơn mn nhiều
Đọc tiếp
Tính
a.\(\sqrt{8+2\sqrt{5}}\) b.\(\sqrt{10-2\sqrt[]{5}}\) c.\(\sqrt{5+\sqrt{24}}\) d.\(\sqrt{12-\sqrt{140}}\)
e.\(\sqrt{14+2\sqrt{5}}\) f. \(\sqrt{8-\sqrt{28}}\) g.\(\sqrt{23-4\sqrt{15}}\) h.\(\sqrt{9+4\sqrt{2}}\)
giúp mik vs mai mik nộp rồi,cảm ơn mn nhiều
1)\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
2)\(\sqrt{35+12\sqrt{6}}-\sqrt{35-12\sqrt{6}}\)
3)\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
Bài 1: Tính
\(\sqrt{3+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\\ \sqrt{12+6\sqrt{3}+\sqrt{12-6\sqrt{3}}}\\ \sqrt{9-4\sqrt{2}+\sqrt{9+4\sqrt{2}}}\)
\(\sqrt{\sqrt{2}+2+\sqrt{4+\sqrt{9-\sqrt{32}}}}\\ \sqrt{6+2\sqrt{5}-\sqrt{29+12\sqrt{5}}}\\ \sqrt{8+\sqrt{8}+\sqrt{20}+\sqrt{40}}-\sqrt{\sqrt{49}+\sqrt{40}}\\ \sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
Rút gọn
\(\dfrac{\left(27+10\sqrt{2}\right)\sqrt{27-10\sqrt{2}}-\left(27-10\sqrt{2}\right)\sqrt{27+10\sqrt{2}}}{\left(\sqrt{\sqrt{13}-3}+\sqrt{\sqrt{13+3}}\right):\sqrt{\sqrt{13}+3}}\)
1) sqrt{12}-sqrt{27}+sqrt{3}
2)sqrt{252}-sqrt{700}+sqrt{1008}-sqrt{448}
3)3sqrt{112}-7sqrt{216}+4sqrt{54}-2sqrt{252}-3sqrt{96}
4)sqrt{18}-3sqrt{80}-2sqrt{50}+2sqrt{45}
5)6sqrt{12}-sqrt{20}-2sqrt{27}+sqrt{125}
6)2sqrt{18}-3sqrt{80}-5sqrt{147}+5sqrt{245}-3sqrt{98}
GIÚP MÌNH VỚI
Đọc tiếp
1) \(\sqrt{12}-\sqrt{27}+\sqrt{3}\)
2)\(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
3)\(3\sqrt{112}-7\sqrt{216}+4\sqrt{54}-2\sqrt{252}-3\sqrt{96}\)
4)\(\sqrt{18}-3\sqrt{80}-2\sqrt{50}+2\sqrt{45}\)
5)\(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
6)\(2\sqrt{18}-3\sqrt{80}-5\sqrt{147}+5\sqrt{245}-3\sqrt{98}\)
GIÚP MÌNH VỚI
Rút gọn biểu thức.
a)\(\sqrt{3+2\sqrt{2}-\sqrt{3-2\sqrt{2}}}\). c)\(\sqrt{5-2\sqrt{6}}+\sqrt{7+2\sqrt{10}}\)
b)\(\sqrt{7-4\sqrt{3}+\sqrt{12+6\sqrt{3}}}\) d)\(\frac{\sqrt{8-2\sqrt{12}}}{\sqrt{3}-1}\)-\(\sqrt{8}\)