\(=4\sqrt{2}\cdot3\sqrt{5}-4\sqrt{2}\cdot4\sqrt{7}\)
\(=4\sqrt{2}\left(3\sqrt{5}-4\sqrt{7}\right)\)
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Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
Tinh:
a)\(\sqrt{10+2\sqrt{14}}.\sqrt{10+2\sqrt{14}}\)
b)\(\sqrt{7+\sqrt{12}}-\sqrt{7-\sqrt{12}}\)
So sánh A = 2\(\sqrt{1}+2\sqrt{3}+2\sqrt{5}+2\sqrt{7}+2\sqrt{9}+2\sqrt{11}+2\sqrt{13}+2\sqrt{15}+2\sqrt{17}+2\sqrt{19}\) và B = \(2\sqrt{2}+2\sqrt{4}+2\sqrt{6}+2\sqrt{8}+2\sqrt{10}+2\sqrt{12}+2\sqrt{14}+2\sqrt{16}+2\sqrt{18}+2\sqrt{20}\)
Rút gọn các biểu thức sau:
H = \(2\sqrt{27}+\sqrt{243}-6\sqrt{12}\)
I = \(\sqrt{14-2\sqrt{ }13}+\sqrt{14+2\sqrt{ }13}\)
K = \(\sqrt{10-\sqrt{ }4\sqrt{ }6}+\sqrt{10\sqrt{ }+4\sqrt{ }6}\)
(*)L = \(\sqrt{6+2\sqrt{ }5-\sqrt{ }29-12\sqrt{ }5}\)
Help me, please!
1.\(\dfrac{\sqrt{8-4\sqrt{3}}}{\sqrt{\sqrt{6}-\sqrt{2}}}\cdot\sqrt{\sqrt{6}+\sqrt{2}}\)
2.\(\sqrt{16-5\sqrt{7}}\left(5\sqrt{2}+\sqrt{14}\right)+\dfrac{6}{3+\sqrt{10}}\)
rút gon bieu thức
left(3sqrt{2}+sqrt{6}right).sqrt{6-3sqrt{3}}
sqrt{12-3sqrt{7}}-sqrt{12+3sqrt{7}}
sqrt{dfrac{13}{4}+sqrt{3}}-sqrt{dfrac{7}{4}-sqrt{3}}
sqrt{dfrac{289+4sqrt{72}}{16}}+sqrt{dfrac{129}{16}+sqrt{2}}
sqrt{11+6sqrt{2}}-sqrt{sqrt{8}+3}
sqrt{16-6sqrt{7}}+sqrt{10-2sqrt{21}}
Đọc tiếp
rút gon bieu thức
\(\left(3\sqrt{2}+\sqrt{6}\right).\sqrt{6-3\sqrt{3}}\)
\(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
\(\sqrt{\dfrac{13}{4}+\sqrt{3}}-\sqrt{\dfrac{7}{4}-\sqrt{3}}\)
\(\sqrt{\dfrac{289+4\sqrt{72}}{16}}+\sqrt{\dfrac{129}{16}+\sqrt{2}}\)
\(\sqrt{11+6\sqrt{2}}-\sqrt{\sqrt{8}+3}\)
\(\sqrt{16-6\sqrt{7}}+\sqrt{10-2\sqrt{21}}\)
Rút gọn:
\(\sqrt{16-8\sqrt{3}}\)
\(\sqrt{38+12\sqrt{2}}\)
\(\sqrt{22+12\sqrt{2}}\)
\(\sqrt{17-12\sqrt{2}}\)
\(\sqrt{20-10\sqrt{3}}\)
So sánh A và B
\(A=\sqrt{12+\sqrt{12+\sqrt{12}}}+\sqrt{6+\sqrt{6+\sqrt{6+\sqrt{6}}}}\)
\(B=\sqrt{14}+\sqrt{11}\)
rút gọn :
a)left(dfrac{sqrt{15}-sqrt{5}}{1-sqrt{3}}+dfrac{sqrt{14}-sqrt{7}}{1-sqrt{2}}right):dfrac{1}{sqrt{7}-sqrt{5}}
b) sqrt{dfrac{3sqrt{3}-4}{2sqrt{3}+1}}+sqrt{dfrac{sqrt{3}+4}{5-2sqrt{3}}}
c) dfrac{2sqrt{5}-5sqrt{2}}{sqrt{2}-sqrt{5}}+dfrac{6}{2-sqrt{10}}+sqrt{67+12sqrt{7}}
d) left(dfrac{sqrt{5}}{sqrt{2}+1}+dfrac{14}{2sqrt{2}-1}-dfrac{6}{2-sqrt{2}}right).sqrt{17-12sqrt{2}}
Đọc tiếp
rút gọn :
a)\(\left(\dfrac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}+\dfrac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}\right):\dfrac{1}{\sqrt{7}-\sqrt{5}}\)
b) \(\sqrt{\dfrac{3\sqrt{3}-4}{2\sqrt{3}+1}}+\sqrt{\dfrac{\sqrt{3}+4}{5-2\sqrt{3}}}\)
c) \(\dfrac{2\sqrt{5}-5\sqrt{2}}{\sqrt{2}-\sqrt{5}}+\dfrac{6}{2-\sqrt{10}}+\sqrt{67+12\sqrt{7}}\)
d) \(\left(\dfrac{\sqrt{5}}{\sqrt{2}+1}+\dfrac{14}{2\sqrt{2}-1}-\dfrac{6}{2-\sqrt{2}}\right).\sqrt{17-12\sqrt{2}}\)
Tính:
\(A=3\sqrt{20}-\sqrt{45}+2\sqrt{18}+\sqrt{72}\)
\(B=\dfrac{12}{3-\sqrt{5}}-\dfrac{16}{\sqrt{5}+1}\)
\(C=10\sqrt{\dfrac{1}{5}}+\dfrac{1}{5}\sqrt{125}-2\sqrt{20}\)
\(E=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{\left(\sqrt{3}-2\right)^2}\)
\(F=\sqrt{6+2\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)