=> \(\dfrac{2\left|x\right|}{3}\)= \(\dfrac{11}{12}-\dfrac{3}{8}\)
=> \(\dfrac{2\left|x\right|}{3}=\dfrac{13}{24}\)
=> |x| = 13.3:24:2 = \(\dfrac{13}{16}\) => x = \(\dfrac{-13}{16}\) hoặc x = \(\dfrac{13}{16}\)
=> \(\dfrac{2\left|x\right|}{3}\)= \(\dfrac{11}{12}-\dfrac{3}{8}\)
=> \(\dfrac{2\left|x\right|}{3}=\dfrac{13}{24}\)
=> |x| = 13.3:24:2 = \(\dfrac{13}{16}\) => x = \(\dfrac{-13}{16}\) hoặc x = \(\dfrac{13}{16}\)
(x+2)/17+(x+4)/15+(x+6)/13=(x+8)/11+(x+10)/9+(x+12)/7
tính nhanh
a) -5/12+4/37+17/12-41/37
b) 1/2+-3/5:(-1/1/2)-|-2/5|
c)8^15 x 3^16/4^22 x 9^8
d)35/1/6:(-4/5)-45/1/6:(-4/5)
e) (5/12:10/3)+(1/2)^2
Tìm x, biết:
a) 3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/ (x+10)(x+7) = x/(x+2)(x+17) với x thuộc {-2,-5,-10,-17}
b) 2/(x-1)(x-3 + 5/(x-3)(x-8) + 12/(x-8)(x-20) -1/x-20 =-3/4 với x thuộc {1,3,8,,20}
HELP ME!!!!
1) Tìm x:
a) \(\frac{11}{12}-\frac{5}{12}.\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
b) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
c) 2x.(x-\(\frac{1}{7}\))=0
d) (x + 1) . (x - 2) < 0
e) (x - 2) . ( x + \(\frac{2}{3}\) ) >0
bài 1: Tìm x biết:
a,\(x+\dfrac{1}{4}=\dfrac{3}{4}\)
b,\(\dfrac{3}{4}-\dfrac{2}{5}x=\dfrac{29}{60}\)
c,\(2x-\dfrac{1}{3}=\dfrac{-5}{6}\)
d,\(2-x:\dfrac{3}{4}=\dfrac{1}{2}\)
e,\(\dfrac{11}{12}-\dfrac{2}{3}|x|=\dfrac{3}{8}\)
f,\(|2x-1|=5\)
lưu ý: Có câu có 2 trường hợp
Các bn giúp mk với
\(\dfrac{11}{12}\)-( \(\dfrac{2}{5}\)+x ) = \(\dfrac{2}{3}\)
Tính bằng cách hợp lí nhất :
1/ \(\left(\frac{4}{9}-\frac{5}{11}\right):\frac{3}{10}+\left(\frac{3}{9}-\frac{9}{11}\right):\frac{3}{10}-\left(\frac{2}{9}-\frac{2}{8}\right).\frac{-10}{3}\)
2/ \(\frac{1}{2}.\frac{1}{-3}+\frac{1}{-3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{-5}+\frac{1}{-5}.\frac{1}{6}\)
3/ \(-\frac{7}{4}\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
Tính:
M = 0,375 -0,3+3/11 +3/12 / -0,625 + 0,5 -5/11-5/12
Tính:
a) \(\dfrac{-3}{4}.\dfrac{12}{-5}.\left(-\dfrac{25}{6}\right);\) b) \(\left(-2\right).\dfrac{-38}{21}.\dfrac{-7}{4}.\left(-\dfrac{3}{8}\right);\)
c) \(\left(\dfrac{11}{12}:\dfrac{33}{16}\right).\dfrac{3}{5};\) d) \(\dfrac{7}{23}.\left[\left(-\dfrac{8}{6}\right)-\dfrac{45}{18}\right].\)