\(\dfrac{x+2}{17}+\dfrac{x+4}{15}+\dfrac{x+6}{13}=\dfrac{x+8}{11}+\dfrac{x+10}{9}+\dfrac{x+12}{7}\)
\(\Leftrightarrow\dfrac{x+2}{17}+1+\dfrac{x+4}{15}+1+\dfrac{x+6}{13}=\dfrac{x+8}{11}+1+\dfrac{x+10}{9}+1+\dfrac{x+12}{7}+1\)
\(\Leftrightarrow\dfrac{x+19}{17}+\dfrac{x+19}{15}+\dfrac{x+19}{13}=\dfrac{x+19}{11}+\dfrac{x+19}{9}+\dfrac{x+19}{7}\)
\(\Leftrightarrow\left(x+19\right)\left(\dfrac{1}{17}+\dfrac{1}{15}+\dfrac{1}{13}-\dfrac{1}{11}-\dfrac{1}{9}-\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow x+19=0\)
\(\Leftrightarrow x=-19\)
Vậy ...
(x+2)/17+(x+4)/15+(x+6)/13-(x+8)/11-(x+10)/9 + (x+12)/7=0
Cộng 1 vào các hạng tử ta được:
(x+19)/17+(x+19)/15+(x+19)/13-(x+19)/11-(x+19)/9-(x+19)/7=0
=> (x+19)(1/17+1/15+1/13-1/11-1/9-1/7)=0
=>x+19=0
=>x=-19
Vậy x= -19
Chúc bạn học tốt!!!
