1. \(a:b:c=2:3:5\) và \(2a+3b-4c=14\)
=> \(\dfrac{a}{2}=\dfrac{b}{4}=\dfrac{c}{5}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{2}=\dfrac{b}{4}=\dfrac{c}{5}=\dfrac{2a+3b-4c}{2.2+3.4-4.5}=\dfrac{14}{-4}=\dfrac{-7}{2}\)
\(\dfrac{a}{2}\Rightarrow a=2.\dfrac{-7}{2}=-7\)
\(\dfrac{b}{4}\Rightarrow b=4.\dfrac{-7}{2}=-14\)
\(\dfrac{c}{5}\Rightarrow c=5.\dfrac{-7}{2}=\dfrac{-35}{2}\)
=> a = -7
b = -14
c = \(\dfrac{-35}{2}\)