Question

1. Cho A = ( \(\frac{x^3-1}{x^2-x}\) - \(\frac{x^3-1}{x^2+x}\) ) : \(\frac{2\left(x^2-2x+1\right)}{x^2-1}\)

B = \(\frac{x+1}{x-2}-\frac{2x}{x+2}-\frac{2+5x}{x^2-4}\)

Hãy rút gọn A và B . Giúp mk lm nha mk cảm ơn nhiều <3

Answer 1

A=(\(\frac{x^3-1}{x\left(x-1\right)}\)-\(\frac{x^3-1}{x\left(x+1\right)}\)) : \(\frac{2\left(x^2-2x+1\right)}{\left(x-1\right)\left(x+1\right)}\)ĐKXĐ: x\(\ne\) -1, 1

A=\(\frac{1}{x\left(x+1\right)}\)x \(\frac{\left(x-1\right)\left(x+1\right)}{2\left(x-1\right)\left(x-1\right)}\)

A=\(\frac{1}{2x^2-2x}\)

B=\(\frac{x+1}{x-2}\)-\(\frac{2x}{x+2}\)-\(\frac{2+5x}{x^2-4}\)ĐKXĐ : x\(\ne\)2, -2

B=\(\frac{x+1}{x-2_{ }}\)-\(\frac{2x}{x+2}\)-\(\frac{2+5x}{\left(x-2\right)\left(x+2\right)}\)

B=\(\frac{x^2+3x+2}{\left(x-2\right)\left(x+2\right)}\)-\(\frac{2x^2-4x}{\left(x-2\right)\left(x+2\right)}\)-\(\frac{2+5x}{\left(x-2\right)\left(x+2\right)}\)

B=\(\frac{-x^2+2x}{\left(x-2\right)\left(x+2\right)}\)

B=\(\frac{-x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}\)

B=\(\frac{-x}{x+2}\)