Question

1, a, Tìm x;y biết:

​(3x-5)^​100+(2y-1)^​200=0

​b, CMR: 6²ⁿ⁺⁴+3ⁿ⁺⁴+3^​n+2 chia hết cho 11

​GIÚP MK VS M.N!!! HELP ME!!!

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Answer 1

a, Với mọi giá trị của x;y ta có:

\(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}\ge0\)

Để \(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}=0\) thì

\(\left\{{}\begin{matrix}\left(3x-5\right)^{100}=0\\\left(2y-1\right)^{200}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}3x-5=0\\2y-1=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=\dfrac{1}{2}\end{matrix}\right.\)

Chúc bạn học tốt!!!

Answer 2

1, Ta có: \(\left\{{}\begin{matrix}\left(3x-5\right)^{100}\ge0\\\left(2y-1\right)^{200}\ge0\end{matrix}\right.\Rightarrow\left(3x-5\right)^{100}+\left(2y-1\right)^{200}\ge0\)

Mà \(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}=0\)

\(\Rightarrow\left\{{}\begin{matrix}\left(3x-5\right)^{100}=0\\\left(2y-1\right)^{200}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=\dfrac{1}{2}\end{matrix}\right.\)

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