\(3x-5-2x\left(5-3x\right)=0\)
\(\Leftrightarrow\left(3x-5\right)+2x\left(3x-5\right)=0\)
\(\Leftrightarrow\left(3x-5\right)\left(1+2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-5=0\\1+2x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x=5\\2x=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-\dfrac{1}{2}\end{matrix}\right.\) \(x^2+3x-10=0\)
\(\Leftrightarrow x^2-2x+5x-10=0\)
\(\Leftrightarrow x\left(x-2\right)+5\left(x-2\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+5=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)
a, \(3x-5-2x\left(5-3x\right)=0\)
\(\Rightarrow3x-5-10x+6x^2=0\)
\(\Rightarrow6x^2-7x-5=0\)
\(\Rightarrow6x^2+3x-10x-5=0\)
\(\Rightarrow3x\left(2x+1\right)-5\left(2x+1\right)=0\)
\(\Rightarrow\left(2x+1\right)\left(3x-5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x+1=0\\3x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{5}{3}\end{matrix}\right.\)
b, \(x^2+3x-10=0\)
\(\Rightarrow x^2-2x+5x-10=0\)
\(\Rightarrow x\left(x-2\right)+5\left(x-2\right)=0\)
\(\Rightarrow\left(x-2\right)\left(x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)
Chúc bạn hoc tốt!!!
