\(A=-1-\dfrac{1}{2}-\dfrac{1}{4}-...-\dfrac{1}{1024}\)
Đặt \(B=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{1024}\)
=>2B=2+1+1/2+...+1/512
=>B=2-1/1024
=>A=-2+1/1024
\(A=-1-\dfrac{1}{2}-\dfrac{1}{4}-...-\dfrac{1}{1024}\)
Đặt \(B=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{1024}\)
=>2B=2+1+1/2+...+1/512
=>B=2-1/1024
=>A=-2+1/1024
-1-1/2-1/4-1/8-...-1/1024
-1-1/2-1/4-1/8-...-1/1024
-1-1/2-1/4-1/8-...-1/1024
Tinh: -1 - 1/2 - 1/4 - 1/8 - ... - 1/1024 .
Giải giúp tớ với :1/2 +1/4+1/8+....+1/1024
-1-\(\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{8}-...-\dfrac{1}{1024}\)
\(\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{8}-...-\dfrac{1}{1024}\)
giúp tớ bài này : 1/2-1/4-1/8-....-1/1024
Help me
a) 2\(\dfrac{2}{7}\)x - \(\dfrac{5}{8}\)=\(\dfrac{17}{24}\)
b) -1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) . . . \(\dfrac{1}{1024}\)
c) \(1\dfrac{1}{24}\). \(3\dfrac{3}{8}\) : \(3\dfrac{3}{4}\)