\(a-b=6\Rightarrow a=6+b\left(1\right)\)
Thay \(\left(1\right)\) vào \(M=\dfrac{3a-b}{2a+6}+\dfrac{3b-a}{2b-6}\left(dk:a\ne-3,b\ne3\right)\)
\(\Rightarrow M=\dfrac{3\left(6+b\right)-b}{2\left(6+b\right)+6}+\dfrac{3b-\left(6+b\right)}{2b-6}\)
\(=\dfrac{18+3b-b}{12+2b+6}+\dfrac{3b-6-b}{2b-6}\)
\(=\dfrac{18+2b}{18+2b}+\dfrac{2b-6}{2b-6}\)
\(=1+1\)
\(=2\)
Vậy \(M=2\) khi \(a-b=6\)
