\(\left|2x-3\right|-\left|3x+2\right|=0\)
⇒ \(\left|2x-3\right|=\left|3x+2\right|\)
⇒ \(\left[{}\begin{matrix}2x-3=3x+2\\2x-3=-\left(3x+2\right)\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}2x-3=2+3\\2x-3=-3x-2\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}-1x=5\\2x+3x=\left(-2\right)+3\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=5:\left(-1\right)\\5x=1\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=-5\\x=1:5\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=-5\\x=\frac{1}{5}\end{matrix}\right.\)
Vậy \(x\in\left\{-5;\frac{1}{5}\right\}.\)
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