Đặt \(z=x+yi\)
\(\left|z-2+3i\right|=3\Leftrightarrow\left|x+yi-2+3i\right|=3\)
\(\Leftrightarrow\left|x-2+\left(y+3\right)i\right|=3\)
\(\Leftrightarrow\sqrt{\left(x-2\right)^2+\left(y+3\right)^2}=3\)
\(\Leftrightarrow\left(x-2\right)^2+\left(y+3\right)^2=9\)