`a)4x^2(x-2)+9(2-x)=0`
`<=>4x^2(x-2)-9(x-2)=0`
`<=>(x-2)(4x^2-9)=0`
`<=>(x-2)(2x-3)(2x+3)=0`
`<=>[(x=2),(x=3/2),(x=-3/2):}`
Vậy `S={2;3/2;-3/2}`
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`c)(2x-1)^2-25=0`
`<=>(2x-1-5)(2x-1+5)=0`
`<=>(2x-6)(2x+4)=0`
`<=>[(x=3),(x=-2):}`
Vậy `S={3;-2}`
\(a,\left(x-2\right)\left(4x^2-9\right)=0\\ \left[{}\begin{matrix}x-2=0\\4x^2-9=0\end{matrix}\right.=>\left[{}\begin{matrix}x-2=0\\2x-3=0\\2x+3=0\end{matrix}\right.=>x=2;x=\dfrac{3}{2};x=-\dfrac{3}{2}\\ c,\left(2x-1-5\right)\left(2x-1+5\right)=0\\ \left(2x-6\right)\left(2x+4\right)=0\\ \left[{}\begin{matrix}2x-6=0\\2x+4=0\end{matrix}\right.=>x=3;x=-2\)
