Câu hỏi của A Thuw

a: \(=\dfrac{x^4-6x^3+12x^2-14x+3}{x^2-4x+1}\)\(=\dfrac{x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3}{x^2-4x+1}\)\(=x^2-2x+3\)b: \(=\dfrac{3x^4-2x^3+x^2-6x^3+4x^2-2x-15x^2+10x-5}{3x^2-2x+1}\)\(=x^2-2x-5\)d: \(=\dfrac{\left(x-4\right)^3}{\left(x-4\right)^2}=x-4\)Câu trả lời: a: \(=\dfrac{x^4-6x^3+12x^2-14x+3}{x^2-4x+1}\)\(=\dfrac{x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3}{x^2-4x+1}\)\(=x^2-2x+3\)b: \(=\dfrac{3x^4-2x^3+x^2-6x^3+4x^2-2x-15x^2+10x-5}{3x^2-2x+1}\)\(=x^2-2x-5\)d: \(=\dfrac{\left(x-4\right)^3}{\left(x-4\right)^2}=x-4\)