Question

Answer 1

`a, = x^2 -12x + 36 = 27`

`=> (x-6)^2= 3 sqrt3`

`=>` \(\left[{}\begin{matrix}x-6=3\sqrt{3}\\x-6=-3\sqrt{3}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=3\sqrt{3}+6\\x=-3\sqrt{3+6}\end{matrix}\right.\)

`b, 4x^2 - 5x - 6= 0`

`<=> 4x(x-2) + 3(x-2)=0`

`<=> (4x+3)(x-2)=0`

`<=>` \(\left[{}\begin{matrix}4x+3=0\\x-2=0\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}x=-\dfrac{3}{4}\\x=2\end{matrix}\right.\)