Question

Answer 1

1: \(B=\dfrac{2x+8+x-4\sqrt{x}-8\sqrt{x}-8}{\left(\sqrt{x}-4\right)\left(\sqrt{x}+1\right)}=\dfrac{3x-12\sqrt{x}}{\left(\sqrt{x}-4\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{3\sqrt{x}}{\sqrt{x}+1}\)

2 Để B<=3/2 thì \(\dfrac{\sqrt{x}}{\sqrt{x}+1}\le\dfrac{1}{2}\)

\(\Leftrightarrow2\sqrt{x}-\sqrt{x}-1< =0\)

=>0<=x<=1