Question

Answer 1

\(a.=>\dfrac{\left(-2\right)^5}{\left(-2\right)^n}=\left(-2\right)^2=>5-n=2=>n=3\\ b.\dfrac{8}{2^n}=2=>2^n=4=>n=2\\ c.=>\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{2}\right)^3=>2n-1=3=>n=2\)

Answer 2

a.=>(−2)5(−2)n=(−2)2=>5−n=2=>n=3

b.82n=2=>2n=4=>n=2

c.=>(12)2n−1=(12)3=>2n−1=3=>n=2