Question

16.2x.(x-1/7)=0

Answer 1

\(16.2x\left(x-\dfrac{1}{7}\right)=0\)

\(\Leftrightarrow32x\left(x-\dfrac{1}{7}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}32x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)

Answer 2

16.2x(x-\(\dfrac{1}{7}\)) = 0

<=> 32x² - \(\dfrac{32}{7}\)x = 0

<=> x(32x-\(\dfrac{32}{7}\)) = 0

<=> \(\left\{{}\begin{matrix}x=0\\32x-\dfrac{32}{7}=0\end{matrix}\right.\)

<=> \(\left\{{}\begin{matrix}x=0\\32x=\dfrac{32}{7}\end{matrix}\right.\)

<=> \(\left\{{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)